>>20
Is there any reason for multi to be a macro? Currently it is the same as
(define (multi f . args)
(for-each f args))If you wrapped it in extra parentheses, it would be just for-each. For example:
(for-each
(lambda (a b) (display (+ a b)) (newline))
'(1 2 3) '(4 5 6))Unless I am missing something.